Class 10 Mathematics Note
Trigonometry
Trigonometry
Area of the triangle =$\frac{1}{2}$base *height
Area of the triangle Δ ABC =$\frac{1}{2}$absinC= $\frac{1}{2}$bcsinA= $\frac{1}{2}$ ca sinB
Example 1
Find the area of the triangle Δ ADE
Area of the Δ ADE = $\frac{1}{2}{\rm{\: }}$area of the rectangle ABCD = $\frac{1}{2}{\rm{\: }}$* 8*10 = 40 cm2
Example 2
In the given figure , If PQ = 8 cm ,QR = 12cm and ∠ PQR= 30° Find the area of Δ PQR
Soln
Area of the Δ PQR = $\frac{1}{2}$sinQ *PQ *QR
Area of the Δ PQR = $\frac{1}{2}$sin30°*8 * 12
Or, Area of the Δ PQR =$\frac{1}{2}$*$\frac{1}{2}$*8 * 12
= 24 cm2
Example 3
Find the length of QT
Area of the Δ PSR = Area of the Δ PQR
Area of the Δ PQR= $\frac{1}{2}{\rm{\: PR\: *QT}}$
16√ 3= $\frac{1}{2}{\rm{\: }}8{\rm{\: *QT}}$
QT =6.9 cm
Height and Distance
Angle of elevation: The angle of elevation is defined as angle between the line of sight and horizontal line made by the observer when the observer observes the object above the horizontal line.
Angle of Depression: The angle of depression is defined as angle between the line of sight and horizontal line made by the observer when the observer observes the object below the horizontal line.
Example 4
A man observes the top of a pole 52cm height situated in front of him and finds the angle of elevation to be 30° .If the distance between man and pole is 86m .Find the height of that man.
Soln
Tan30° =$\frac{{{\rm{ED}}}}{{{\rm{AD}}}}$=$\frac{{{\rm{ED}}}}{{86}}$
$\frac{1}{{\sqrt 3 }}$=$\frac{{{\rm{ED}}}}{{86}}$
Or, ED = $\frac{{86}}{{\sqrt 3 }}$
Or, ED = 49.65cm
Height of man (DC) = EC – ED = 50- 47.65 =2.35 m
Example 5
The angle of elevation from the roof of a house to the top of atop of tree is found to be 30°. If the height of the house and tree are 8 m and 20m respectively, find the distance between the house and the tree.
Soln
ED = EC - DC = 20- 8 = 12 cm
Tan 30°=$\frac{{{\rm{ED}}}}{{{\rm{AD}}}}$
$\frac{1}{{\sqrt 3 }}$=$\frac{{12}}{{{\rm{AD}}}}$
AD =20.78 cm
∴ Distance between tree and house is20.78 cm