Class 9 Mathematics Note
SIMPLE INTEREST
Simple interest
Simple interest is the additional amount of money we borrow or deposit certain amount of money after certain interval of time. It is calculated as I = $\frac{{{\rm{PTR}}}}{{100}}$
When the simple interest is added to the principal and the interest is taken from that money, it is called compound interest.
Some Important terms for the calculation of simple interest
Principal: It is the initial amount of money borrowed or deposited.
P =$\frac{{{\rm{A*}}100}}{{100 + {\rm{TR\: }}}}$
P =$\frac{{100{\rm{*I}}}}{{{\rm{TR}}}}{\rm{\: }}$
Time: It is the intervalof time for which money is deposited or borrowed.
T =$\frac{{100{\rm{*I}}}}{{{\rm{PR}}}}{\rm{\: }}$
Rate: It is the interest on Rs 100 for 1 year .It is expressed in %.
R =$\frac{{100{\rm{*I}}}}{{{\rm{PT}}}}{\rm{\: }}$
Amount: It is the sum of principal and interest.
A = P + I
Examples
1. What sum of money deposited at 10% p.a wiil yield the same interest in 4 years as Rs 1680 yields in 5 years at 12 % p.a .
Soln
Principal (p1 ) =Rs 1680
Time (T 1 ) = 4years
Rate (R1 )=10%
I1=$\frac{{{{\rm{P}}_1}{{\rm{T}}_1}{{\rm{R}}_1}}}{{100}}{\rm{\: }}$
= $\frac{{1680{\rm{*}}4{\rm{*}}10}}{{100}}$
=Rs 672
Again,
Principal (p2 ) =?
Time (T2 ) = 5 years
Rate (R2 )=12%
p2= $\frac{{{{\rm{I}}_2}{\rm{*}}100}}{{{{\rm{T}}_2}{{\rm{R}}_2}}}$
= $\frac{{672{\rm{*}}100}}{{5{\rm{*}}12}}$
= 1120
2.
A sum of money amounts to Rs 1380 in 3 years and to Rs 1500 in 5 years .Find the sum and rate of interest.
Soln
Amount (A1 ) = Rs 1380
Time (T1 ) = 3years
Principal = Rs P
Rate = R %
P = $\frac{{{{\rm{A}}_1}{\rm{*}}100}}{{100 + {{\rm{T}}_1}{\rm{R}}}}$
P = $\frac{{1380{\rm{*}}100}}{{100 + 3{\rm{*R}}}}$……………..i
Also,
Amount (A2) = Rs 1500
Time (T2) = 5 years
Principal = Rs P
Rate = R %
P = $\frac{{{{\rm{A}}_2}{\rm{*}}100}}{{100 + {{\rm{T}}_1}{\rm{R}}}}$
P =$\frac{{1500{\rm{*}}100}}{{100 + 5{\rm{*R}}}}$……………………..ii
From I and ii
We get
$\frac{{1380{\rm{*}}100}}{{100 + 3{\rm{*R}}}}$=$\frac{{1500{\rm{*}}100}}{{100 + 5{\rm{*R}}}}$
100+ 5R = 108 + 3.24R
R= 4.54%
3. Find simple interest on Rs. 10,000 for1$\frac{1}{2}$years at the rate of 5% per annum. Also find total amount.
Solution:
Let Principal = 10,000, Rate = 5% =5 /100 =0.05,
Time =$1\frac{1}{2}$ years =(1+$\frac{{1{\rm{\: }}}}{2}$)years =${\rm{\: }}\frac{3}{{{\rm{\: }}2}}$years
I = $\frac{{{\rm{PTR}}}}{{100}}$
=$10,000{\rm{*}}\frac{3}{2}{\rm{*}}0.05$
=750
Amount= Principal + Interest = 10000 + 750 =Rs 10750